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Quiz of the Month (January 2001)
Hector C. Parr
***
SOLUTION TO LAST MONTH'S QUIZ
1) 2758620689655172413793103448
2) 15
3) 4 hours, 1 and 1/239 minutes
or 4 hours, 1 minute, 60/239 seconds
Notes
1). Take the unknown number (ending with 8), multiply
it by 3, and copy each digit of the product into
the multiplicand. Stop when 8 appears in the
product without a carry digit.
2). J + K = 24
J = 2(K  x) (x years ago)
J  x = 0.5(K + y) (y years hence)
K + y = 3(J  z) (z years ago)
J  z = 3(K  z)
Solving, J = 15, K = 9, x = 1.5, y = 18, z = 6
3). 1434 clock minutes = 1440 real minutes
So 240 clock minutes = 240 X 1440/1434 real minutes
= 241 and 6/1434 real minutes
= 241 and 1/239 real minutes.

THIS MONTH'S QUIZ
1. What is the smallest number (greater than 1) which
leaves a remainder of 1 when divided by 2, by 3, by
4, by 5, by 6, by 7 and by 8?
2. What is the greatest possible number of occasions during
a year (not a leap year) on which a Friday falls on the
13th day of a month, and in which months do they occur?
3. The following multiplication sums are correct, but some
of the numbers have got lost. Fill in the missing numbers.
(i) *1*9 (ii) ****
X * X *3
*2*87 *****
===== 8*575
******
======

***
(c) Hector C. Parr (2001)
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