HOME

TREATISE:
. Quantum
Nodal Theory

ROMALDKIRK:
. Village
. Reservoirs

ESSAYS: COSMOLOGY
. Infinity
. Universe
. Dark Matter

ESSAYS: PHILOSOPHY
. Free Will
. Representation
. Conditionals
. Postscript

ESSAYS: ORGAN MUSIC
. Practising
. British Organs
. Hymn Playing
. Music Lovers

QUIZ QUESTIONS
. Quiz Archive

SERVICES
. Book Reviews

Quiz of the Month (December 2006)

Hector C. Parr

***

SOLUTION TO LAST MONTH'S QUIZ

  1.  1/6 ft3  
  2.  1/3 ft3
  3.  1.155 ft

Notes.
  1. Taking EFH as base and A as vertex,
     Volume = 1/3 * 1/2 * 1 = 1/6

  2. Volume of remainder = 1 - 4 * 1/6 = 1/3

  3. AFH is an equilateral triangle with sides sqr(2)
       So area AFH = ... = sqr(3)/2

     Taking AFH as base and CP as height,
       Volume = 1/3 * sqr(3)/2 * CP
       So 1/3 = 1/3 * sqr(3)/2 * CP
       So CP = 2/sqr(3)

THIS MONTH'S QUIZ

  There are seven ways of dividing four people, A, B, C and D,
  into two (non-empty) groups, namely:
      1. (A)  (BCD)
      2. (B)  (ACD)
      3. (C)  (ABD)
      4. (D)  (ABC)
      5. (AB) (CD)
      6. (AC) (BD)
      7. (AD) (BC)
  
  1. In how many ways can five people be divided into two groups?

  2. In how many ways can ten people be divided into two groups?

  3. In how many ways can ten people be divided into three groups?
***

© Hector C. Parr (2006)

Go to Quiz Archive

Back to Home Page