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 Quiz of the Month (August 2002)
Hector C. Parr
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SOLUTION TO LAST MONTH'S QUIZ
1. 10 cm/sec
2. 150 cm
3. 37.4 sec 

Notes
1. Suppose speed on carpet = v cm/sec
So speed on floor = 1.25 v
So 200/1.25v + 400/v = 56
Solving, v = 10
2. This question is easy for anyone who realises that it
is analogous to the wellknown problem in optics of
a ray of light emerging from a block of glass whose
refractive index is 1.25. Angle ECF is equal to the
critical angle, so its sine is 1/1.25 = 0.8, and ECF
is a 345 triangle with sides 90, 120 and 150 cm.
3. CF = 150 cm and FD = 400  120 = 280 cm.
So time = 150/10 + 280/12.5 = 37.4 sec

THIS MONTH'S QUIZ
1. Two bells are tolling at regular intervals. The first bell strikes every 1.95 seconds and the second bell strikes every 2.20 seconds. If both bells strike at noon, after how many seconds will they again strike exactly together?
2. A listener cannot separate the sound of the two bells unless the interval between their strokes is more than 0.05 seconds. How many seconds after noon will the two bells next appear to sound together again?
3. Three bells are tolling at intervals of 1.95 seconds, 2.15 seconds, and 2.20 seconds respectively. If all three bells strike at noon, after how long will they all strike again exactly together?

***
(c) Hector C. Parr (2002)
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