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## Quiz of the Month (August 2000)

### Hector C. Parr

***

#### SOLUTION TO LAST MONTH'S QUIZ

```           1) Time shown = 7:47

2) 22 times

3) 21 and 9/11 minutes past 4.

Notes
No.3 can easily be solved by forming an equation, but
you might prefer this method:

At 4 o'clock the angle between the pointers is 120
degrees, so the minute hand must gain 120 degrees on the
hour hand to overtake it.

Now the minute hand gains 330 degrees in 60 mins.
So it gains 120 degrees in 60 X 120/330 = 21 9/11 mins.
```

#### THIS MONTH'S QUIZ

```  Alan Wilkinson, a local schoolmaster and historian,
published a booklet a few years ago entitled "Twenty
Family Walks". In the preface he writes, "The walks are
short, ranging from a mile and a half to five miles; the
average is two and a half miles."

Using only this information, answer the following:

1. What is the total length of all twenty walks?

2. What is the greatest possible number of walks over
four miles long?

3. If there are three walks of five miles each, what is
the greatest possible number of walks less than five
miles but over two and a half miles?
```

***

(c) Hector C. Parr (2001)

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